A battery is formed by connecting three cells in series .
The emfs of cells are 5 V, 2.5 V and 1.5 V and their internal resistance are `0.5 Omega ,0.05 Omega and 0.45 Omega` respectively.
This battery is connected across a load resistance of `5 Omega` what current will be supplied by the battery ? if the cell of emf 1.5 V were connected with reverse polarity then what would have been the current supplied by the battery ?

Explanation

To solve the problem step by step, we will first calculate the total EMF and total internal resistance of the battery formed by the three cells connected in series. Then, we will find the current supplied by the battery when connected to a load resistance of 5 ohms. Finally, we will analyze the scenario where the cell with 1.5 V is connected with reverse polarity.

### Step 1: Calculate the Total EMF of the Battery
The total EMF (E) of the battery formed by connecting the three cells in series is the sum of the individual EMFs of the cells.

\[ E = E_1 + E_2 + E_3 \]
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