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State Wheatstone bridge principle and de...

State Wheatstone bridge principle and deduce it using Kirchhoff's rules.

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Principle of Wheatstone bridge. It state that if the ratio of the two resistance `((P)/(Q))` on the one edge is equal to the ratio of the two resistance `((R )/(S))` in another edge, then there will be no flow of current between the mid points of the two edges of resistance. Condition of balanced Wheatstone Bridge. `(P)/(Q) = (R )/(S)`
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Questions|Wheatstone Bridge

(a) State Kirchhoff's rules for an electirc network. Using Kirchhoff's rules, obtain the balance condition in terms of the resistances of four arms of Wheatstone bridge. (b) In the meter bridge experimental set up, shown in the figure, the null point 'D' is obtained at a distance of 40 cm from end A of the meter bridge wire. If a resistance of 10 Omega is connected in series with R_(1), null point is obtained at AD = 60 cm. Calculate the values of R_(1) and R_(2).

Wheatstone Bridge and Symmetry Circuit

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