How many electrons pass through a lamp in 2 minutes, if the current is 300 mA. Given that charge on an electron is `1.6 xx 10^(-19)C`.

Explanation

Given `t= 2 xx 60 = 120s, I = 300mA= 300 xx 10^(-3)A, n=`?
`:. n= (It)/(e ) = (300 xx 10^(-3) xx 120)/(1.6 xx 10^(-19))= 22.5 xx 10^(19)` electrons