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There is one metallic rod AB whose area ...

There is one metallic rod AB whose area of cross section decreases from its end A towards the end B. End A of the rod is connected to positive terminal of a battery and end B is connected to its negative terminal. If one moves in a direction from B to A,

A

the magnitude of the current will increase

B

the magnitude of current will decrease

C

the magnitude of drift velocity will decrease

D

the magnitude of drift velocity will increase

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To solve the problem step by step, we will analyze the situation of the metallic rod AB with a decreasing cross-sectional area from end A to end B, which is connected to a battery. ### Step 1: Understanding the Setup - We have a metallic rod AB where the area of cross-section decreases from A to B. - End A is connected to the positive terminal of a battery, and end B is connected to the negative terminal. **Hint:** Visualize the rod and the direction of current flow from A to B. ### Step 2: Current Flow in the Rod - When current flows through the rod, the same amount of charge must flow through any cross-section of the rod at any point in time due to the conservation of charge. - Therefore, the current (I) remains constant throughout the rod. **Hint:** Remember that current is the flow of charge and is conserved in a closed circuit. ### Step 3: Analyzing Cross-Sectional Area - As we move from B to A, the cross-sectional area (A) of the rod increases. - The relationship between current (I), charge density (n), charge (e), area (A), and drift velocity (Vd) is given by the equation: \[ I = n \cdot e \cdot A \cdot V_d \] **Hint:** Identify how the area affects the drift velocity in the equation. ### Step 4: Finding Drift Velocity - Rearranging the equation gives: \[ V_d = \frac{I}{n \cdot e \cdot A} \] - Since I is constant and n (number density of charge carriers) and e (charge of an electron) are also constants, we can see that drift velocity (Vd) is inversely proportional to the area (A). - As we move from B to A, since A is increasing, Vd must decrease. **Hint:** Focus on the inverse relationship between drift velocity and area. ### Step 5: Conclusion - Therefore, the magnitude of the drift velocity will decrease as we move from B to A. **Final Answer:** The magnitude of drift velocity will decrease.

To solve the problem step by step, we will analyze the situation of the metallic rod AB with a decreasing cross-sectional area from end A to end B, which is connected to a battery. ### Step 1: Understanding the Setup - We have a metallic rod AB where the area of cross-section decreases from A to B. - End A is connected to the positive terminal of a battery, and end B is connected to the negative terminal. **Hint:** Visualize the rod and the direction of current flow from A to B. ...
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MODERN PUBLICATION-CURRENT ELECTRICITY-Objective Type Questions (MULTIPLE CHOICE QUESTIONS) (A. MULTIPLE CHOICE QUESTIONS WITH ONLY ONE CORRECT ANSWER)
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  10. In an experiment a student measures terminal potential difference (TPD...

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  11. When two terminals of a cell are directly connected to each other, cur...

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  12. n identical cells, each of emf epsilon and internal resistance r, are ...

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  13. In the previous question what will be the terminal potential differenc...

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  14. One capacitor and ammeter connected in series are connected to an idea...

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  15. How many time constants will elapse before a capacitor gains 99% of it...

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  16. How many time constans will elapse before a fully charged capacitor lo...

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  17. A resistance of 5Omega is connected across the left gap of a metrebrid...

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  18. Current flowing in 20 Omega resistance in the given circuit is

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  19. Consider the following circuit diagram. C(1)//C(2) = 1//2 A switch is ...

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  20. A 4mu F capacitor is connected to a battery of emf 24V. Through a resi...

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