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There is one metallic rod AB whose area ...

There is one metallic rod AB whose area of cross section decreases from its end A towards the end B. End A of the rod is connected to positive terminal of a battery and end B is connected to its negative terminal. If one moves in a direction from B to A,

A

the magnitude of the current will increase

B

the magnitude of current will decrease

C

the magnitude of drift velocity will decrease

D

the magnitude of drift velocity will increase

Text Solution

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The correct Answer is:
To solve the problem step by step, we will analyze the situation of the metallic rod AB with a decreasing cross-sectional area from end A to end B, which is connected to a battery. ### Step 1: Understanding the Setup - We have a metallic rod AB where the area of cross-section decreases from A to B. - End A is connected to the positive terminal of a battery, and end B is connected to the negative terminal. **Hint:** Visualize the rod and the direction of current flow from A to B. ### Step 2: Current Flow in the Rod - When current flows through the rod, the same amount of charge must flow through any cross-section of the rod at any point in time due to the conservation of charge. - Therefore, the current (I) remains constant throughout the rod. **Hint:** Remember that current is the flow of charge and is conserved in a closed circuit. ### Step 3: Analyzing Cross-Sectional Area - As we move from B to A, the cross-sectional area (A) of the rod increases. - The relationship between current (I), charge density (n), charge (e), area (A), and drift velocity (Vd) is given by the equation: \[ I = n \cdot e \cdot A \cdot V_d \] **Hint:** Identify how the area affects the drift velocity in the equation. ### Step 4: Finding Drift Velocity - Rearranging the equation gives: \[ V_d = \frac{I}{n \cdot e \cdot A} \] - Since I is constant and n (number density of charge carriers) and e (charge of an electron) are also constants, we can see that drift velocity (Vd) is inversely proportional to the area (A). - As we move from B to A, since A is increasing, Vd must decrease. **Hint:** Focus on the inverse relationship between drift velocity and area. ### Step 5: Conclusion - Therefore, the magnitude of the drift velocity will decrease as we move from B to A. **Final Answer:** The magnitude of drift velocity will decrease.

To solve the problem step by step, we will analyze the situation of the metallic rod AB with a decreasing cross-sectional area from end A to end B, which is connected to a battery. ### Step 1: Understanding the Setup - We have a metallic rod AB where the area of cross-section decreases from A to B. - End A is connected to the positive terminal of a battery, and end B is connected to the negative terminal. **Hint:** Visualize the rod and the direction of current flow from A to B. ...
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