Three cells of emf, `epsi_(1) = 1.5 V, epsi_(2) = 2.0 V and epsi_(3) = 3.0 V` having internal resistance `r_(1) = 0.30 Omega, r_(2) = 0.4 Omega and r_(3) = 0.6 Omega` respectively are connected in parallel. Find out the equivalent emf and the equivalent resistance of a cell which can replace this combination.

Explanation

To solve the problem of finding the equivalent emf and the equivalent resistance of three cells connected in parallel, we will follow these steps:

### Step 1: Write down the given values
We have three cells with the following parameters:
- Cell 1: \( \epsilon_1 = 1.5 \, \text{V} \), \( r_1 = 0.30 \, \Omega \)
- Cell 2: \( \epsilon_2 = 2.0 \, \text{V} \), \( r_2 = 0.40 \, \Omega \)
- Cell 3: \( \epsilon_3 = 3.0 \, \text{V} \), \( r_3 = 0.60 \, \Omega \)

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