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A 100 W heater coil is rated 200 V. Find...

A 100 W heater coil is rated 200 V. Find the resistance of thwe coil.

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To find the resistance of a heater coil rated at 100 W and 200 V, we can use the formula for electrical power: \[ P = \frac{V^2}{R} \] Where: - \( P \) is the power in watts (W) - \( V \) is the voltage in volts (V) - \( R \) is the resistance in ohms (Ω) ...
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MODERN PUBLICATION-CURRENT ELECTRICITY-REVISION EXERCISES (NUMERICAL PROBLEMS)
  1. A copper wire is stretched so as to increase its length by 0.2%. Calcu...

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  2. Estimate the average drift speed of conduction electrons in a copper w...

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  3. A uniform wire of resistance 12 Omega is cut into three pieces so that...

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  4. A battery of emf E and internal resistance when connected across an ex...

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  5. Three cells of emf, epsi(1) = 1.5 V, epsi(2) = 2.0 V and epsi(3) = 3.0...

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  6. A 100 W heater coil is rated 200 V. Find the resistance of thwe coil.

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  7. Two bulbs are reled (P(1),V)" and "(P(2), V). If they are connected (...

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  8. A 16 Omega resistance wire is bent to form a square. A source of emf 9...

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  9. Use Kricchoff's rules to find out the values of the current I(1) and I...

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  10. In the electric network shown in the figure use Krichhoff's rules to c...

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  11. A potentiometer wire of length 1 m is connected to a driver cell of em...

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  12. A potentiometer wire of length 1.0 m has a resistance of 10 Omega. It ...

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  13. In the circuit shown, R(1) = 4 Omega, R(2) = R(3) = 15 Omega, R(4) = 3...

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  14. In the circuit shown in the figure, find the total resistance of the c...

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  15. A resistance of R Omega draws current from a potentiometer as shown in...

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  16. For the circuit shown here, would tha balancing length increase, decre...

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  17. The potential difference applied across a given resistor is altered so...

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  18. Thirty six cells each of emf 1.5 V and internal resistance 0.5 Omega a...

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  19. A potentiometer has 10 wires each of 1 metre length and the total resi...

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  20. A metallic wire of length l and resistance 5 Omega is stretched to dou...

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