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In the electric network shown in the fig...

In the electric network shown in the figure use Krichhoff's rules to calculate the power consumed by the resistance `R = 8 Omega`

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In loop EADFE [Even, data error as per the diagram given] `-(I_(1) + I_(2)) 8 +8 = 0`
`I_(1) + I_(2) = 1`
Power consumerd by the resistance R will be `P = (I_(1) + I_(2))^(2) R= 1 xx 8`
`rArr P= 8W`
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