A potentiometer has 10 wires each of 1 metre length and the total resistance is `20 Omega`. Find the resistance to be connected to the driving battery of emf 2 volts to produce a potential drop of `1 mu V` per millimetre. (Graph sheet is not required.)

A potentiometer wire has length 8m and resistance 16Omega . The resistance that must be conneted in series with the wire and an accumulator of emf 4V, so as to get a potential gradient of 1mV per cm on the wire is

A potentiometer wire is 10 m long and has a resistance of 2 Omega//"m". It is connected in series with a battery of e.m.f. 3 V and a resistance of 10Omega . The potential gradient along the wire in V/m is

A potentiometer wire is 10 m long and has a resistance of 18Omega . It is connected to a battery of emf 5 V and internal resistance 2Omega . Calculate the potential gradient along the wire.

A potentiometer wire of length 1m has a resistance 20Omega .It is connected in series with a resistance R and a cell of emf 2 volts.If potential gradient is 1V/m .Find R

A potentiometer wire of length 10m and resistance 20Omega is connected in series with another resistance of 80Omega and a battery of emf 4V . The potential gradient on the wire will be (in mV//cm )

A wire of length 1.6m has a resistance 8 Omega is connected to a battery of 2 volts and internal resistance 2Omega . What is the potential gradient ?

The resistance of a potentiometer wire of length 10 m is 20 Omega . A resistance box and a 2 volt accumulator are connected in series with it. What resistance should be introduced in the box to have a potential drop of one microvolt per millimetre of the potentiometer wire ?

A cell of e.m.f 1.5V and negligible internal resistance is connected in series with a potential meter of length 10 m and total resistance 20 Omega . What resistance should be introduced in the resistance box such that the potential drop across the potentiometer is one microvolt per cm of the wire?