Two resistors R and 3 R are connected in series. Ratio of rate of heat dessipated in R to that in 3 R is `x_(1)`. Similarly when R and 3 R are connected in parallel to each other, ratio of the heat dessipated in R to that in 3 R is `x_(2)`. What will be the value of `x_(2)//x_(1)`?

Options

A. 9
B. `1//9`
C. 6
D. `1//6`

Answer

A

Explanation

In case of series combination of resistors, same current flows through both the resistors. So using `H = i^(2)R` we get `x_(1) = 1//3`
In case of parallel combination same potential difference is applied across both the resistors. So using `H= V^(2)//R` we get `x_(2) = 3`. Hence `(x_(2))/(x_(1)) = 9`. so, option (a) is correct