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A carbon resistor of (47 +- 4.7) k Omega...

A carbon resistor of `(47 +- 4.7) k Omega` is to be marked with rings of different colours for its identification. The colour code sequence will be

A

Yellow-Green-Violet-Gold

B

Yellow-Violet-Orange-Silver

C

Violet-Yellow-Orange-Silver

D

Green-Orange-Violet-Gold

Text Solution

Verified by Experts

The correct Answer is:
B
`(47 +- 4.7) k Omega = 47 xx 10^(3) +- 10%`
Corresponding colours are as follows:
`:.` (Yellow) (Violet) `xx 10^("orange") +-` Silver
Hence option (b) is correct
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