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Number of atoms of oxygen present in 10....

Number of atoms of oxygen present in 10.6 g `Na_(2)CO_(3)` will be

A

`6.022 xx 10^(22)`

B

`12.04 xx 10^(22)`

C

`1.806 xx 10^(23)`

D

`31.80 xx 10^(28)`

Text Solution

Verified by Experts

The correct Answer is:
C
Molar mass of `Na_(2)CO_(3) = 2 xx 23 + 12 + 3 xx 16 = 106 g mol^(-1)`
`therefore 10.6 g Na_(2)CO_(3) =0.1 mol`
`=0.1 xx 6.02 xx 10^(23)` molecules
`=3 xx 0.1 xx 6.02 xx 10^(23)` atoms of `O = 1.806 xx 10^(23)`
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