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A gas mixture contains 50% helium and 50...

A gas mixture contains 50% helium and 50% methane by volume. What is the percent by weight of methane in the mixture?

A

`19.97%`

B

`20%`

C

`50%`

D

`80%`

Text Solution

Verified by Experts

The correct Answer is:
D
Equal volumes contain equal number of moles, Hence molar ratio of He : `CH_(4) =1:1`
`therefore` Ratio by weight `=4:16 = 1:4`
`therefore CH_(4)` present by weight `=4/5 xx 100 = 80%`
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