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The volume of water to be added to 100 c...

The volume of water to be added to 100 cm of 0.5 N `H_(2)SO_(4)` to get decinormal concentration is

A

100 `cm^(3)`

B

`450 cm^(3)`

C

`500 cm^(3)`

D

`400 cm^(3)`

Text Solution

Verified by Experts

The correct Answer is:
D
`N_(1)V_(1) = N_(2)V_(2)`, i.e. `0.5 xx 100 = 0.1 xx V_(2)` or, `V_(2) = 500 cm^(3`.
`therefore` Water to be added to `100 cm^(3)` solution.
`=500 - 100 = 400 cm^(3)`.
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