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In acidic medium, the equivalent weight ...

In acidic medium, the equivalent weight of `K_(2)Cr_(2)O_(7)` (molecular weight = M) is

A

M

B

M/2

C

M/3

D

M/6

Text Solution

Verified by Experts

The correct Answer is:
D
Equivlent weight `=("Molecular weight")/("Change in oxidation state/valency/no. of electron involved")`
Reaction involved is
`Cr_(2)O_(7)^(2-) + 14H^(+) + 6e^(-) to 2Cr^(3+) + 7H_(2)O`
It is quite clear that in this reaction, `Cr(+6)` is reduced to `Cr(+3)`.
`therefore` Equivalent weight of `K_(2)Cr_(2)O_(7) = ("Mol. wt")/6 = M/6`
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