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In the crystalline solid MSO(4).nH(2)O ...

In the crystalline solid `MSO_(4).nH_(2)O` of molar mass 250 `g mol^(-1)`, the percentage of anhydrous salt is 64 by weight. The value of n is

A

2

B

3

C

5

D

7

Text Solution

Verified by Experts

The correct Answer is:
C
Mass of anhydrous `MSO_(4)` salt `=64/100 xx 250 = 160` g/mole
Total mass of `H_(2)O` in `MSO_(4).nH_(2)O = 250-160 = 90` g/mole
Therefore, the value of n `=90/18 =5`
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