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If loga/(b-c) = logb/(c-a) = logc/(a-b),...

If `loga/(b-c) = logb/(c-a) = logc/(a-b)`, then `a^(b+c).b^(c+a).c^(a+b)`=

A

1

B

2

C

`-1`

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
A
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