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If the fractional part of the number (2^...

If the fractional part of the number `(2^(403))/(15)` is `(k)/(15)`, then `k` is equal to

A

14

B

6

C

4

D

8

Text Solution

AI Generated Solution

The correct Answer is:
To find the value of \( k \) such that the fractional part of \( \frac{2^{403}}{15} \) is \( \frac{k}{15} \), we can follow these steps: ### Step 1: Rewrite \( 2^{403} \) We can express \( 2^{403} \) as: \[ 2^{403} = 2^{400} \times 2^3 = (2^{100})^4 \times 8 \] ### Step 2: Simplify \( 2^{400} \) We can simplify \( 2^{400} \) further: \[ 2^{400} = (2^4)^{100} = 16^{100} \] Thus, we have: \[ 2^{403} = 8 \times 16^{100} \] ### Step 3: Express \( 16^{100} \) in terms of \( 15 \) Next, we can express \( 16^{100} \) in a form that can be expanded using the binomial theorem: \[ 16^{100} = (15 + 1)^{100} \] Using the binomial theorem, we can expand this: \[ (15 + 1)^{100} = \sum_{k=0}^{100} \binom{100}{k} 15^k \cdot 1^{100-k} \] ### Step 4: Identify the terms The expansion gives us: \[ (15 + 1)^{100} = 1 + \binom{100}{1} \cdot 15 + \binom{100}{2} \cdot 15^2 + \ldots + 15^{100} \] The first term \( 1 \) is the integer part, and all other terms involve powers of \( 15 \). ### Step 5: Multiply by \( 8 \) Now, multiplying the entire expansion by \( 8 \): \[ 8 \cdot (15 + 1)^{100} = 8 + 8 \cdot \left( \binom{100}{1} \cdot 15 + \binom{100}{2} \cdot 15^2 + \ldots + 15^{100} \right) \] ### Step 6: Divide by \( 15 \) Now, we divide the entire expression by \( 15 \): \[ \frac{8 \cdot (15 + 1)^{100}}{15} = \frac{8}{15} + \frac{8 \cdot \left( \binom{100}{1} \cdot 15 + \binom{100}{2} \cdot 15^2 + \ldots + 15^{100} \right)}{15} \] The first term \( \frac{8}{15} \) is the fractional part we are interested in. ### Step 7: Identify \( k \) From the expression, we can see that the fractional part of \( \frac{2^{403}}{15} \) is \( \frac{8}{15} \). Therefore, \( k \) is equal to \( 8 \). ### Final Answer Thus, the value of \( k \) is: \[ \boxed{8} \]

To find the value of \( k \) such that the fractional part of \( \frac{2^{403}}{15} \) is \( \frac{k}{15} \), we can follow these steps: ### Step 1: Rewrite \( 2^{403} \) We can express \( 2^{403} \) as: \[ 2^{403} = 2^{400} \times 2^3 = (2^{100})^4 \times 8 \] ...
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