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`A B` is a diameter of a circle and `C` is any point on the circle. Show that the area of ` A B C` is maximum, when it is isosceles.

A

the area of `DeltaABC` is maximum when it is isosceles

B

the area of `Delta ABC` is minimum whne it is isosceles

C

the perimeter of `DeltaABC` is minimum when it is isosceles

D

None of the above

Text Solution

Verified by Experts

The correct Answer is:
A
Clearly, `angleC = 90^(@)` as angle in semi-circle is right angled. Now, area of triangle is maximum when AC=BC.
i.e., Triangle is right angled isosceles.
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