The line x+3y=0 is a diameter of the cir...

The line `x+3y=0` is a diameter of the circle `x^2+y^2-6x+2y=0`

Text Solution

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The correct Answer is:

Since, centre of circle is (3, -1) which lies on x + 3y = 0 `rArr x + 3y = 0 " is diameter of " x^(2) + y^(2)-6x + 2y = 0`
Hence, given statement is true.

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If the line x + 2by + 7 = 0 is a diameter of the circle x^(2) + y^(2) - 6x + 2y = 0 , then : b =

`- 5`

`-1`

Which of the following line is a diameter of the circel x ^(2) + y^(2) -6x-8y-9=0 ?

`3x-4y =0`

`4x-y=0`

`x+y=7`

`x-y=1`

The equation of a diameter of circle x ^(2) + y^(2)-6x + 2y =0, passing through origin is

`x+3y=0`

`x-3y =0`

`3x+ y=0`

`3x-y=0`