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The line x+3y=0 is a diameter of the cir...

The line `x+3y=0` is a diameter of the circle `x^2+y^2-6x+2y=0`

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The correct Answer is:
1
Since, centre of circle is (3, -1) which lies on x + 3y = 0 `rArr x + 3y = 0 " is diameter of " x^(2) + y^(2)-6x + 2y = 0`
Hence, given statement is true.
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