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If one of the diameters of the circle x^...

If one of the diameters of the circle `x^2+y^2-2x-6y+ 6 = 0` is a chord to the circle with centre (2, 1), then the radius of circle is:

A

`sqrt3`

B

`sqrt2`

C

3

D

2

Text Solution

Verified by Experts

The correct Answer is:
C
Here, radius of smaller circle, AC`=sqrt(1^(2)+3^(2)-6)=2` Clearly, from the figure the radius of bigger circle
`r^(2)=2^(2)+[(2-1)^(2)+(1-3)^(2)]`
`r^(2)=9 rArr r = 3`
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