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If the circles x^2+y^2+2x+2ky+6=0 and x^...

If the circles `x^2+y^2+2x+2ky+6=0` and `x^2+y^2+2ky+k=0` intersect orthogonally then k equals

A

2 or -3/2

B

`-2 or -3//2`

C

2 or 3/2

D

`-2 or 3//2`

Text Solution

Verified by Experts

The correct Answer is:
A
Since, the given circles intersect orthogonally.
`therefore 2(1) (0)+2(k)(k)=6+k`
`[therefore2g_(1)+2f_(1)f_(2)=c_(1)+c_(2)]`
`rArr 2k^(2)-k-6=0rArrk=-(3)/(2),2`
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