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Tangents drawn from the point P(1, 8) to...

Tangents drawn from the point `P(1, 8)` to the circle `x^2+ y^2-6x-4y-11=0` touch the circle at the points `A` and `B`. The equation of the circumcircle of the triangle `PAB` is

A

`x^(2)+y^(2)+4x-6y+19=0`

B

`x^(2)+y^(2)-4x-10y+19=0`

C

`x^(2)+y^(2)-2x+6y-29=0`

D

`x^(2)+y^(2)-6x-4y+19=0`

Text Solution

Verified by Experts

The correct Answer is:
B
For required circle, P(1, 8) and O(3 , 2) will be the end point of its diameter.
`therefore(x-1)(x-3)+(y-8)(y-2)=0`
`rArrx^(2)+y^(2)-4x-10y+19=0`
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