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Predict all order of reactivity of the f...

Predict all order of reactivity of the following compounds in dehydrohalogenation.
a,. I. `CH_(3)CH_(2)CH_(2)CH_(2)Cl`
II. `(CH_(3))_(2)CHCH_(2)Cl`
III. `(CH_(3))_(2)CH - CH_(2)Br`
IV. `CH_(3)CH(Br)CH_(2)CH_(3)`
V. `(CH_(3))_(3) C - Br`
b. I. `CH_(3)CH(Br)CH_(3)`
II. `CH_(3)CH_(2)CH_(2)Br`
III. `(CH_(3))_(2) CH - CH_(2) Br`
IV. `(CH_(3))_(3)C - CH_(2) Br`

Text Solution

Verified by Experts



Ease fo dehdrohalogenation is due to the formation of carbocation and the stability of carbocation is `3^(@) gt 2^(@) gt 1^(@)`, and case of fornation of carbocation is `(R-1) gt (R-Br) gt (R-Cl)`
So the order of dehydrogenation is `(V) gt (III) gt (II) gt (IV) gt (I)`.
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Predict the order of reactivity of the following compounds in dehydrohalogenation: (a) CH_(3)CH_(2)CH_(2)CH_(2)Cl, (CH_(3))_(2)CHCH_(2)Cl, (CH_(3))_(2)CH-CH_(2)Br, CH_(3)CH(Br)CH_(2)CH_(3), (CH_(3))_(3)C-Br (b) CH_(3)CH(Br)CH_(3), CH_(3)CH_(2)CH_(2)Br, (CH_(3))_(2)CHCH_(2)Br, (CH_(3))_(3)C CH_(2)Br

Predict the order of reactivity of the following compounds in dehydrohalogenation: (a) CH_(3)CH_(2)CH_(2)CH_(2)Cl, (CH_(3))_(2)CHCH_(2)Cl, (CH_(3))_(2)CH-CH_(2)Br, CH_(3)CH(Br)CH_(2)CH_(3), (CH_(3))_(3)C-Br (b) CH_(3)CH(Br)CH_(3), CH_(3)CH_(2)CH_(2)Br, (CH_(3))_(2)CHCH_(2)Br, (CH_(3))_(2)C CH_(2)Br

Knowledge Check

  • Increasing order of reactivity of the following alkyl halides in the Williamson's synthesis is I. CH_(2)=CHCH_(2)Cl II. CH_(3)CH_(2)CH_(2)Br III. (CH_(3))_(3)C CH_(2)Br IV. CH_(3)CH_(2)CH_(2)Cl

    A
    `IIltIIIltIVltI`
    B
    `IIIltIIltIVltI`
    C
    `IVltIIIltIltII`
    D
    `IIIltIVltIIltI`
  • Give the decreasing order of reactivity of the following alkyl halides in the Williamson's reaction. i. (CH_(3))_(3)C-CH_(2)Br ii. CICH_(2)CH=CH_(2) iii. (CICH_(2)CH_(2)CH_(3) iv. BrCH_(2)CH_(2)CH_(3)

    A
    ii gt iv gt iii gt i
    B
    i gt iii gt iv gt ii
    C
    ii gt iii gt iv gt i
    D
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  • Decreasing order of reactivity in Williamson's ether synthesis of the following is: I. Me_(3)C CH_(2)Br II. CH_(3)CH_(2)CH_(2)Br III. CH_(3)=CHCH_(2)Cl IV. CH_(3)CH_(2)CH_(2)Cl

    A
    IIIgtIIgtIVgtI
    B
    IgtIIgtIVgtIII
    C
    IIgtIIIgtIVgtI
    D
    IgtIIIgtIIgtIV
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