The partial pressure of ethane over a solution containing `6.56 xx 10^(-3) `g of ethane is 1 bar. If the solution contains `5.00 xx 10^(-2)` g of ethane, then what shall be the partial pressure of the gas ?

Explanation

Applying the relationship `m = K_H xx p` (Henry.s law)
In the first case, `6.56 xx 10^(-2) g = K_H x `
1 bar or `K_H = 6.56 xx 10^(-2)g "bar"^(-1)`
Let the partial pressure in the second case be p.
In the second case, `5.00 xx 10^(-2) g = (6.56 xx 10^(-2) g "bar"^(-1)) xxp`
`p = (5.00 xx 10^(-2) g)/(6.56 xx 10^(-2) g "bar"^(-1)) = 0.762` bar