At 300 K, 36 g of glucose present in a litre of its solution has an osmotic pressure of 4.98 bar. If the osmotic pressure of the solution is 1.52 bars at the same temperature, what would be its concentration ?

Explanation

Applying the relation :
`pi = CRT`
In the first case, ` = 36/1880 xx R xx 300 = 60 R ` ....(i)
In the second case, `1.52 = C xx R xx 300 `(C is concentration) ....(ii)
Dividing (ii) by (i), we get
`C = 0.061 M`