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Give reasons for the following: Where ...

Give reasons for the following:
Where R is an alkyl group , `R_3P=O` exists but `R_3N=O` does not .

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There are no d-orbitals in the valence shell in N, therefore the covalency of N is restricted to four. Therefore, it cannot form the compound `R_3N=O` which requires the valency of five. However, I can expand its covalency to five and form compounds like `R_3P=O`.
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Give reasons for the following : (i) Where R is an alkyl group, R_(3)P=O" exists but "R_(3)N=O does not. (ii) PbCl_(4) is more covalent than PbCl_(2). (iii) At room temperature, N_(2) is much less reactive.

Why does R_3P=0 exist but R_3N=0 does not (R= alkyl group)?

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