The sum of some terms of G. P. is 315 whose first term and the common ratio are 5 and 2, respectively. Find the last term and the number of terms.

Explanation

Sum of n terms = 315


a(`(r^n−1)/(r−1)`) = 315


5(`(2^n−1)/(2−1)`) = 315


`(2^n−1)` = 63


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