The half-life of C^(14 is 5760 years.for...

The half-life of `C^(14` is 5760 years.for a 200 mg sample of`C^(14)` , the time taken to change to 25 mg is

11520 years

23040 years

5760 years

17280 years.

Text Solution

Verified by Experts

The correct Answer is:

`R_(0) = 200 mg , R = 25 mg , R = 25 mg , t_(1//2) = 5720` years
Suppose required years are x.
Also, suppose no. of half lives = n
`:. (R/(R_0))= (1/2)^n implies (25/100) = (1/2)^(n)`
`implies (1/8) = (1/2)^(n) implies (1/2)^(3) = (1/2)^(n) implies n = 3`
`:. n = x/(5760) implies 3 = x/(5760) implies x = 5760 xx 3 = 17280` years.

Topper's Solved these Questions

RADIOACTIVITY AND NUCLEAR CHEMISTRY
MTG-WBJEE|Exercise WB JEE PREVIOUS YEARS QUESTIONS (CATEGORY 2 : SINGLE OPTION CORRECT TYPE)|1 Videos
RADIOACTIVITY AND NUCLEAR CHEMISTRY
MTG-WBJEE|Exercise WB JEE WORKOUT (CATEGORY 3 : ONE OR MORE THAN ONE CORRECT TYPE)|10 Videos
PRINCIPLES OF QUALITATIVE ANALYSIS
MTG-WBJEE|Exercise WB JEE PREVIOUS YEARS QUESTIONS (CATEGORY 2 : Single Option Correct Type)|2 Videos
REDOX EQUILIBRIA
MTG-WBJEE|Exercise WB JEE PREVIOUS YEARS QUESTIONS|5 Videos

The half-life of `C^(14` is 5760 years.for a 200 mg sample of`C^(14)` , the time taken to change to 25 mg is

Text Solution

Topper's Solved these Questions

Similar Questions

MTG-WBJEE-RADIOACTIVITY AND NUCLEAR CHEMISTRY -WB JEE PREVIOUS YEARS QUESTIONS (CATEGORY 1 : SINGLE OPTION CORRECT TYPE)