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Deduce the expression, N=N(0)^(-lambdat)...

Deduce the expression, `N=N_(0)^(-lambdat)` for the law of radioactive decay.
(b) Is the nucleus formed in the decay of the nucleus `._(11)^(12)Na`, an isotope or isobar?

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Since new nucleus has the same mass number, hence it would be an Isobar.
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(a) Write symbolically the process expressing the beta^(+) decay of ._11Na^(22) . Also write the basic nuclear process underlying this decay. (b) Is the nucleus formed in the decay of the nucleus ._11Na^(22) , an isotope or isobar?

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