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If the line ax+by+c=0 is normal to the c...

If the line `ax+by+c=0` is normal to the curve `xy+5=0`, then

A

`a gt0, b gt0`

B

`b gt 0, a lt 0`

C

`blt0, a gt0`

D

none of these

Text Solution

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The correct Answer is:
To solve the problem, we need to find the conditions under which the line \( ax + by + c = 0 \) is normal to the curve defined by \( xy + 5 = 0 \). ### Step 1: Understand the curve The given curve is \( xy + 5 = 0 \). We can rewrite this as \( xy = -5 \). This represents a hyperbola. ### Step 2: Differentiate the curve To find the slope of the tangent to the curve, we differentiate \( xy + 5 = 0 \) implicitly with respect to \( x \): \[ \frac{d}{dx}(xy) + \frac{d}{dx}(5) = 0 \] Using the product rule on \( xy \): \[ y + x\frac{dy}{dx} = 0 \] Rearranging gives: \[ \frac{dy}{dx} = -\frac{y}{x} \] ### Step 3: Find the slope of the normal The slope of the normal line is the negative reciprocal of the slope of the tangent. Therefore, if the slope of the tangent is \( -\frac{y}{x} \), the slope of the normal is: \[ \text{slope of normal} = \frac{x}{y} \] ### Step 4: Relate the normal's slope to the line equation The equation of the line is \( ax + by + c = 0 \). We can rearrange this to find the slope: \[ by = -ax - c \implies y = -\frac{a}{b}x - \frac{c}{b} \] Thus, the slope of this line is \( -\frac{a}{b} \). ### Step 5: Set the slopes equal Since the line is normal to the curve, we set the slopes equal: \[ \frac{x}{y} = -\frac{a}{b} \] This implies: \[ x \cdot b = -a \cdot y \] ### Step 6: Substitute for \( xy \) From the curve equation \( xy = -5 \), we can express \( y \) in terms of \( x \): \[ y = -\frac{5}{x} \] Substituting this into the equation \( x \cdot b = -a \cdot y \): \[ x \cdot b = -a \left(-\frac{5}{x}\right) \implies bx^2 = 5a \] ### Step 7: Analyze the signs From \( bx^2 = 5a \), we can analyze the signs: - If \( b > 0 \), then \( a \) must also be positive for the equation to hold true. - If \( b < 0 \), then \( a \) must also be negative. Thus, we conclude that \( \frac{a}{b} > 0 \). ### Conclusion The line \( ax + by + c = 0 \) is normal to the curve \( xy + 5 = 0 \) if \( a \) and \( b \) have the same sign. Therefore, we can summarize the conditions as: - \( a > 0 \) and \( b > 0 \) or - \( a < 0 \) and \( b < 0 \).
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