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Let f: R->R be given by f(x)=[x]^2+[x+1]...

Let `f: R->R` be given by `f(x)=[x]^2+[x+1]-3` , where `[x]` denotes the greatest integer less than or equal to `x` . Then, `f(x)` is (a) many-one and onto (b) many-one and into (c) one-one and into (d) one-one and onto

A

f(x) is many - one and into function

B

f(x) = 0 for infinite number of values of x

C

f(x) = 0 for only two real values of x

D

none of these

Text Solution

Verified by Experts

The correct Answer is:
A, B
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