Using section formula, show that the points `A (2, -3, 4)`, `B (-1, 2, 1)`and `C(0,1/3,2)`are collinear.

Explanation

To show that the points \( A(2, -3, 4) \), \( B(-1, 2, 1) \), and \( C(0, \frac{1}{3}, 2) \) are collinear using the section formula, we can follow these steps:

### Step 1: Understand the Section Formula
The section formula states that if a point \( C(x, y, z) \) divides the line segment joining points \( A(x_1, y_1, z_1) \) and \( B(x_2, y_2, z_2) \) in the ratio \( m:n \), then the coordinates of point \( C \) can be expressed as:
\[ C\left(\frac{mx_2 + nx_1}{m+n}, \frac{my_2 + ny_1}{m+n}, \frac{mz_2 + nz_1}{m+n}\right) \]

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