A body cools from `80^(@)C` to `50^(@)C` in 5 min-utes Calculate the time it takes to cool from `60^(@)C` to `30^(@)C` The temperature of the surroundings is `20^(@)C` .

Explanation

To solve the problem of how long it takes for a body to cool from \(60^\circ C\) to \(30^\circ C\) given that it cools from \(80^\circ C\) to \(50^\circ C\) in 5 minutes, we will use Newton's Law of Cooling.

### Step-by-Step Solution:

1. **Identify the Given Data:**
- Initial temperature \(T_2 = 80^\circ C\)
- Final temperature \(T_1 = 50^\circ C\)
- Time taken \(t = 5\) minutes
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