A loaded truck of mass 3000 kg moves on a level road at a constant speed of 6.00 0 m/s. The frictional force on the truck from the road is 1000 N. Assume that air drag is negligible.
(a) How much work is done by the truck engine in 10.00 min ?

Explanation

To find the work done by the truck engine in 10 minutes, we can follow these steps:

### Step 1: Understand the Problem
The truck is moving at a constant speed of 6.00 m/s and is subject to a frictional force of 1000 N. Since it moves at a constant speed, the engine must exert a force equal to the frictional force to maintain that speed.

### Step 2: Calculate the Force Exerted by the Engine
The force exerted by the truck engine (F_engine) must be equal to the frictional force to maintain constant speed:
\[ F_{\text{engine}} = F_{\text{friction}} = 1000 \, \text{N} \]
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