A capacitor of unknown capacitance is connected across a battery of V volts . The charge stored in it is `360 mu C` . When potential across the capacitor is reduced by 120 V , the charge stored in it becomes 120 `mu C ` . Calculate :
What will be the charge stored in the capacitor , if the voltage applied had increased by 120 V ?

Explanation

When the potential applied is increased by 120 V , the potential becomes `V. = (V +120 )` volt = `(180 + 120)` volt = 300 volt
`therefore` Charge on capacitor `Q. = C V. = 2 mu F xx 300` volt = `600 mu C`