Three identical capacitors `C_1 , C_2` and `C_3` of capacitance `6 mu F ` each are connected to a 12 V battery as shown in Fig

charge on each capacitor

Explanation

The capacitor arrangement can be redrawn as shown in Fig
Combined capacitance of series arrangement of `C_1` and `C_2` is `C_(12) = (C_(1) xx C_(2))/(C_(1) + C_(2)) = (6 xx 6)/(6 + 6) mu F = 3 mu F `
`therefore q_1 = q_2 = C_(12) . V = 3 mu F xx 12 V = 36 mu C` and `q_(3) = C_(3) V = 6 mu F xx 12 V = 72 mu C`