Home
Class 11
PHYSICS
A saturn year is 29.5 times the earth ye...

A saturn year is 29.5 times the earth year. How far is the saturn from the sun if the earth is `1.5xx10^(8)` away from the sun?

A

`1.2 xx 10^9 km`

B

`1.3 xx 10^9 km`

C

`1.4 xx 10^9 km`

D

`1.5 xx 10^9 km`

Text Solution

Verified by Experts

The correct Answer is:
C
Here `T_s = 29.5 T_e, R_e = 1.5 xx 10^8 km , R_s = ?`
According to kepler.s third law , `T^2 prop R^3`
` therefore (T_s^2)/(T_e^2) = (R_s^3)/(R_e^3)`
`R_s = R_e (T_s/T_e)^(2//3) = 1.5 xx 10^8 ((29.5 T_e)/(T_e))^(2//3) = 1.4 xx 10^9 km`
Promotional Banner

Topper's Solved these Questions

  • GRAVITATION

    MTG GUIDE|Exercise NEET CAFE TOPICWISE PRACTICE QUESTIONS (UNIVERSAL LAW OF GRAVITATION)|15 Videos

  • GRAVITATION

    MTG GUIDE|Exercise NEET CAFE TOPICWISE PRACTICE QUESTIONS (ACCELERATION DUE TO GRAVITY AND ITS VARIATION WITH ALTITUDE AND DEPTH)|19 Videos

  • GRAVITATION

    MTG GUIDE|Exercise AIPMT/NEET MCQS|32 Videos

  • BEHAVIOUR OF PERFECT GAS AND KINETIC THEORY

    MTG GUIDE|Exercise AIPMT / NEET (MCQs)|11 Videos

  • KINEMATICS

    MTG GUIDE|Exercise AIPMT/ NEET MCQs|31 Videos

Similar Questions

Explore conceptually related problems

How far is the sun from the earth?

A certain planet's year is 8 times the earth's year. Find the distance of this planet from the sun if the distance of the earth is 1 AU from the sun.

Express the average distance of the earth from the sun in light year.

It takes Earth one year to orbit the sun.

The earth receives at its surface radiation from the sun at the rate of 1400 Wm^-2. The distance of the centre of the sun from the surface of the earth is 1.5xx10^11 m and the radius of the sun is 7xx10^8m. Treating the sun as a black body, it follows from the above data taht its surface temperature is ......K

The period of revolution of a planet around the sun is 8 times that of the earth. If the mean distance of that planet from the sun is r, then mean distance of earth from the sun is

The sun's angular diameter is measured to be 1920''. The distance of the sun from the earth is 1.496xx10^(11)m. What is the diameter of the sun?

A comet of mass 10^(8) kg travels around the sun in an elliptical orbit . When it is closed to the sun it is 2.5 xx 10 ^(11) m away and its speed is 2 xx 10 ^(4) m s^(-1) Find the change in kinetic energy when it is farthest from the sun and is 5 xx 10 ^(10) m away from the sun