If `g_E` and `g_M` are the acceleration due to gravity on the surfaces of the earth and the moon respectively and if Millikan's oil drop experiment could be performed on the two surfaces, one will find the ratio
electronic charge on the moon/electronic charge on the earth to be

Options

A. `(g_M)/(g_L)`
B. 1
C. 0
D. `(g_E)/(g_M)`

Answer

B

Explanation

Since electronic charge `(e = 1.6 xx 10^(-19) C)` is a universal constant . It does not depend on the value of acceleration due to gravity.
` therefore ` Electronic charge on the moon=electronic charge on the earth
electronic charge on the moon / electronic charge on the earth= 1