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Two sides of a triangular field are 85 m...

Two sides of a triangular field are 85 m and 154 m in length and its perimeter is 324 m. Find (i) the area of the field and (ii) the length of the perpendicular from the opposite vertex on the side measuring 154 m.

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To solve the problem step by step, we will find the area of the triangular field using Heron's formula and then calculate the length of the perpendicular from the opposite vertex to the side measuring 154 m. ### Step 1: Identify the sides of the triangle Given: - Side A = 85 m - Side B = 154 m - Perimeter = 324 m To find the third side (C), we use the perimeter: \[ C = \text{Perimeter} - (A + B) \] \[ C = 324 - (85 + 154) \] \[ C = 324 - 239 = 85 \text{ m} \] ### Step 2: Calculate the semi-perimeter (s) The semi-perimeter (s) is half of the perimeter: \[ s = \frac{A + B + C}{2} \] \[ s = \frac{85 + 154 + 85}{2} \] \[ s = \frac{324}{2} = 162 \text{ m} \] ### Step 3: Apply Heron's formula to find the area (A) Heron's formula for the area of a triangle is given by: \[ \text{Area} = \sqrt{s \cdot (s - A) \cdot (s - B) \cdot (s - C)} \] Substituting the values: \[ \text{Area} = \sqrt{162 \cdot (162 - 85) \cdot (162 - 154) \cdot (162 - 85)} \] \[ = \sqrt{162 \cdot 77 \cdot 8 \cdot 77} \] \[ = \sqrt{162 \cdot 77^2 \cdot 8} \] ### Step 4: Simplify the area calculation Calculating \( 77^2 \): \[ 77^2 = 5929 \] Now substituting back: \[ \text{Area} = \sqrt{162 \cdot 5929 \cdot 8} \] \[ = \sqrt{162 \cdot 47432} \] \[ = \sqrt{7693440} \] Calculating \( \sqrt{7693440} \): \[ \text{Area} \approx 2772 \text{ m}^2 \] ### Step 5: Find the length of the perpendicular (h) from the opposite vertex to the base (154 m) Using the area formula for a triangle: \[ \text{Area} = \frac{1}{2} \times \text{base} \times \text{height} \] Where the base is 154 m and the area is 2772 m²: \[ 2772 = \frac{1}{2} \times 154 \times h \] ### Step 6: Solve for height (h) Rearranging the equation: \[ h = \frac{2 \times 2772}{154} \] \[ h = \frac{5544}{154} \] \[ h \approx 36 \text{ m} \] ### Final Answers (i) The area of the triangular field is approximately **2772 m²**. (ii) The length of the perpendicular from the opposite vertex on the side measuring 154 m is **36 m**.
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RS AGGARWAL-AREAS OF TRIANGLES AND QUADRILATERALS-Exercise 14
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  2. The perimeter of a triangular field is 540 m and its sides are in the ...

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  3. Two sides of a triangular field are 85 m and 154 m in length and its p...

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  4. Find the area of an isosceles triangle each of whose equal sides measu...

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  5. The base of an isosceles triangle measures 80 cm and its area is 360 c...

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  6. The perimeter of an isosceles triangle is 32 cm. The ratio of the equa...

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  7. The perimeter of a triangle is 50 cm. One side of the triangle is 4 cm...

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  8. The triangular side walls of a flyover have been used for advertisemen...

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  9. The perimeter of an isosceles triangle is 42 cm and its base is 1(1)/(...

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  10. The area of an equilateral triangle is 36 sqrt(3) cm^(2). Its perimete...

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  11. If the area of an equilateral triangle is 81 sqrt(3) cm^(2), find its ...

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  12. Each side of an equilateral triangle measures 8 cm. Find (i) the area ...

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  13. The height of an equilateral triangle measures 9 cm. Find its area, co...

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  14. The base of a right-angled triangle measures 48 cm and its hypotenuse ...

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  15. The sides of a quadrilateral ABCD taken in order are 6 cm, 8 cm, 12 cm...

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  16. The area of a trapezium is 475 cm^(2) and its height is 19 cm. Find th...

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  17. A field is in the shape of a trapezium having parallel sides 90 m and ...

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  18. A rectangular plot is given for constructing a house, having a measure...

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  19. A rhombus-shaped sheet with perimerter 40 cm and on e diagonal 12 cm, ...

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  20. The difference between the semi perimeter and the sides of a Delta ABC...

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