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The base of an isosceles triangle measur...

The base of an isosceles triangle measures 80 cm and its area is 360 `cm^2`. Find the perimeter of the triangle.

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The correct Answer is:
162 cm

`(1)/(2) xx 80 cm xx h = 360 cm^(2) rArr h = (360)/(40)cm = 9 cm`.
`AB^(2) = (40 cm)^(2) + h^(2) = (40 cm)^(2)+(9 cm)^(2) = 1681 cm^(2)`
`rArr" "AB = sqrt(1681) cm = 41 cm`.
`therefore" "AC = AB = 41 cm`.
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RS AGGARWAL-AREAS OF TRIANGLES AND QUADRILATERALS-Exercise 14
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  4. The perimeter of an isosceles triangle is 32 cm. The ratio of the equa...

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  5. The perimeter of a triangle is 50 cm. One side of the triangle is 4 cm...

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  9. If the area of an equilateral triangle is 81 sqrt(3) cm^(2), find its ...

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  10. Each side of an equilateral triangle measures 8 cm. Find (i) the area ...

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  11. The height of an equilateral triangle measures 9 cm. Find its area, co...

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  13. The sides of a quadrilateral ABCD taken in order are 6 cm, 8 cm, 12 cm...

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  14. The area of a trapezium is 475 cm^(2) and its height is 19 cm. Find th...

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  15. A field is in the shape of a trapezium having parallel sides 90 m and ...

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  16. A rectangular plot is given for constructing a house, having a measure...

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