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The area of a trapezium is 475 cm^(2) an...

The area of a trapezium is 475 `cm^(2)` and its height is 19 cm. Find the lengths of its two parallel sides if one side is 4 cm greater than the other.

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To solve the problem, we will use the formula for the area of a trapezium: \[ \text{Area} = \frac{1}{2} \times (a + b) \times h \] where \( a \) and \( b \) are the lengths of the two parallel sides, and \( h \) is the height. ### Step 1: Identify the variables Let: - \( x \) = length of the shorter parallel side - \( x + 4 \) = length of the longer parallel side (since it is 4 cm greater than the shorter side) ### Step 2: Write the area formula Given that the area of the trapezium is 475 cm² and the height is 19 cm, we can substitute these values into the area formula: \[ 475 = \frac{1}{2} \times (x + (x + 4)) \times 19 \] ### Step 3: Simplify the equation First, simplify the expression inside the parentheses: \[ x + (x + 4) = 2x + 4 \] Now, substitute this back into the area equation: \[ 475 = \frac{1}{2} \times (2x + 4) \times 19 \] ### Step 4: Eliminate the fraction Multiply both sides by 2 to eliminate the fraction: \[ 950 = (2x + 4) \times 19 \] ### Step 5: Divide by 19 Now, divide both sides by 19: \[ \frac{950}{19} = 2x + 4 \] Calculating \( \frac{950}{19} \): \[ 50 = 2x + 4 \] ### Step 6: Solve for \( x \) Now, subtract 4 from both sides: \[ 50 - 4 = 2x \] \[ 46 = 2x \] Now, divide by 2: \[ x = 23 \] ### Step 7: Find the lengths of the parallel sides Now that we have \( x \), we can find the lengths of the two parallel sides: - Shorter side \( a = x = 23 \) cm - Longer side \( b = x + 4 = 23 + 4 = 27 \) cm ### Final Answer The lengths of the two parallel sides are: - Shorter side: 23 cm - Longer side: 27 cm ---

To solve the problem, we will use the formula for the area of a trapezium: \[ \text{Area} = \frac{1}{2} \times (a + b) \times h \] where \( a \) and \( b \) are the lengths of the two parallel sides, and \( h \) is the height. ...
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RS AGGARWAL-AREAS OF TRIANGLES AND QUADRILATERALS-Exercise 14
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