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The difference between the lengths of the parallel sides of a trapezium is 8 cm, the perpendicular distance between these sides is 24 cm and the area of the trapezium is 312 `cm^(2)`. Find the length of each of the parallel sides.

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To solve the problem, we need to find the lengths of the two parallel sides of the trapezium, given the following information: 1. The difference between the lengths of the parallel sides (L2 - L1) is 8 cm. 2. The perpendicular distance between the parallel sides (height, h) is 24 cm. 3. The area of the trapezium is 312 cm². Let's denote: - L1 = length of the shorter parallel side - L2 = length of the longer parallel side ### Step 1: Set up the equations From the information given, we can set up the following equations: 1. **Equation 1 (from the difference of lengths)**: \[ L2 - L1 = 8 \quad \text{(1)} \] 2. **Equation 2 (from the area of the trapezium)**: The area \( A \) of a trapezium is given by the formula: \[ A = \frac{1}{2} \times (L1 + L2) \times h \] Plugging in the values we have: \[ 312 = \frac{1}{2} \times (L1 + L2) \times 24 \quad \text{(2)} \] ### Step 2: Simplify Equation 2 To simplify Equation 2, we can multiply both sides by 2 to eliminate the fraction: \[ 624 = (L1 + L2) \times 24 \] Now, divide both sides by 24: \[ L1 + L2 = \frac{624}{24} = 26 \quad \text{(3)} \] ### Step 3: Solve the system of equations Now we have two equations: 1. \( L2 - L1 = 8 \) (Equation 1) 2. \( L1 + L2 = 26 \) (Equation 3) We can solve these equations simultaneously. From Equation 1, we can express \( L2 \) in terms of \( L1 \): \[ L2 = L1 + 8 \quad \text{(4)} \] ### Step 4: Substitute Equation 4 into Equation 3 Now substitute Equation 4 into Equation 3: \[ L1 + (L1 + 8) = 26 \] This simplifies to: \[ 2L1 + 8 = 26 \] Subtract 8 from both sides: \[ 2L1 = 18 \] Now divide by 2: \[ L1 = 9 \quad \text{(5)} \] ### Step 5: Find \( L2 \) Now substitute \( L1 \) back into Equation 4 to find \( L2 \): \[ L2 = 9 + 8 = 17 \quad \text{(6)} \] ### Conclusion The lengths of the parallel sides of the trapezium are: - \( L1 = 9 \) cm - \( L2 = 17 \) cm
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RS AGGARWAL-AREAS OF TRIANGLES AND QUADRILATERALS-Exercise 14
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  5. Each side of an equilateral triangle measures 8 cm. Find (i) the area ...

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  8. The sides of a quadrilateral ABCD taken in order are 6 cm, 8 cm, 12 cm...

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  10. A field is in the shape of a trapezium having parallel sides 90 m and ...

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