Following is the frequency distribution of the total marks obtained by the students of all sections of a class in an examination:

Draw a histogram for the above given distribution.

Explanation

In the given frequency distribution, the class intervals are not of equal width. So, we would make modifications in the heights of rectangles in the histogram in such a way that the areas of rectangles are proportional to the frequencies.
Here, minimum class size `= 50.`
Height of the rectangle for a given class interval
`={("its frequency")/("its width")xx50}`
For example, the height for class interval 300-500 is `=((80)/(200)xx50)=20`
Thus, we have

nce along the `x`-axis we do not start with 0, so we use a kink in the beginning.
Now, we draw rectangles with given class intervals along the `x`-axis on a suitable scale and their corresponding heights along the `y`-axis on another suitable scale. Thus, we obtain the histogram of the given data, as shown below.