Factroize
`(i) (x^3-x)`
`(ii) 18a^2x^2-32)`
`(iii) (2a^5-32a)`.

Explanation

We have
`(i) (x^3-x)=(x^2 -1)`
`=x(x-1)(x+1)`
`therefore(x^3-x)=x(x-1)(x+1)`.
`(ii) (18a^2x^2-32) =2(9a^2x^2-16)`
` =2xx[(3ax)^2-4^2]`
` =2(3ax-4)(3ax+4)`
`therefore (18a^2x^2-32)=2(3ax-4)(3ax+4)`.
`(iii) (2a^5-32a)=2a(a^4-16)`
`=2axx [(a^2)^2-4^2]`
` =2a(a^2-4)(a^2+4)`
` =2a (a-2)(a+2)(a^23+4)`
` therefore (2a^5-32a)=2a(a-2)(a+2)(a^2+4)`