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Factorize: x^3+3x^2+3x-7...

Factorize: `x^3+3x^2+3x-7`

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We have
`x^3+3x^2+3x-7`
` =(x^3+3x^2+3x+1)-7-1`
`=(x+1)^3-8=(x+1)^3-2^3`
` =(x+1-2)xx{(x+1)^2+2(x+1)+2^2}`
`=(x-1)(x^2+4x+7)`.
` therefore (x^3+3x^2+3x-7)=(x-1)(x^2+4x+7)`.
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