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8x^3+y^3+27 z^3-18 x y z...

`8x^3+y^3+27 z^3-18 x y z`

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We have
`8x^3+y^3+27x^3-18xyz`
`=(2x)^3+y^3+(3z)^3-3xx(2x)xxyxx (3z)`
`=a^3+b^3+c^3-3abc, " where " 2x=a,y=b and 3z =c `
`=(a+b+c)(a^2+b^2+c^2-ab-bc-ca)`
`=(2x+y+3z)(4x^2+y^2+9z^2-2xy-3yz-6xz)`.
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