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Factorise a^3-8b^3-64c^3-24abc...

Factorise `a^3-8b^3-64c^3-24abc`

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We have
`a^3-8b^3-64c^3-24abc`
`=(9a)^3+(-2b)^3+(-4c)^3-3xxa xx (-2b)xx (-4c)`
`=x^3+y^3 z^3-3xyz, " where" a=x, -2b=y and -4c =z`
`=(x+y+z)(x^2+y^2+z^2-xy-yz-zx)`
`=(a-2b-4c)(a^2+4b^2+16c^2+2ab-8bc+4ac)`.
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