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factorize : 108a^2-3(b-c)^2...

factorize : `108a^2-3(b-c)^2`

Text Solution

Verified by Experts

The correct Answer is:
`3(6a+b-c)(6a-b+c)`
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The expression (a-b)^(3)+(b-c)^(3)+(c-a)^(3) can be factorized as (a)(a-b)(b-c)(c-a)(b)3(a-b)(b-c)(c-a)(c)-3(a-b)(b-c)(c-a)(d)(a+b+c)(a^(2)+b^(2)+c^(2)-ab-bc-ca)