Home
Class 9
MATHS
Solve 16x^4-1 =0. Find the value of x...

Solve `16x^4-1` =0. Find the value of x

Text Solution

Verified by Experts

The correct Answer is:
`(2x-1)(2x+1)(4x^2+1)`
Promotional Banner

Topper's Solved these Questions

  • FACTORISATION OF POLYNOMIALS

    RS AGGARWAL|Exercise Exercise 3C|66 Videos

  • FACTORISATION OF POLYNOMIALS

    RS AGGARWAL|Exercise Exercise 3D|7 Videos

  • FACTORISATION OF POLYNOMIALS

    RS AGGARWAL|Exercise Exercise 3A|34 Videos

  • COORDINATE GEOMETRY

    RS AGGARWAL|Exercise Multiple Choice Questions (Mcq)|22 Videos

  • GEOMETRICAL CONSTRUCTIONS

    RS AGGARWAL|Exercise Exercise 13|2 Videos

Similar Questions

Explore conceptually related problems

Solve 16x^(2)+4=0

1/8 -(2x)/4 + 1 = 0 , find the value of x

If ( x + 1 )( x + 4 ) - ( x -2 )( x - 1 ) = 0 , find the value of x

In the expression 2.5 + 0.05 -[1.6 -{3.2 -(3.2 +2.1 div x)}] =0.65 find the value of x .

Solve 8x^(2)-16x=0 .

If the polynomial 4x^(3)-16x^(2)+ax+7 is exactly divisible by x-1, then find the value of a. Hence factorise the polynomial.

The mean of the numebrs 1,4,9, X ,12,14,15 and 16 is 10. Find the value of X

The first three terms in the expansion of (1+ax)^(n)(n!=0) are 1,6x and 16x^(2). Then find the value of a and n.

If, x = 3 +i then find the value of the expression x^4-4x^3+4x^2-16x+60 .