Prove that
`(i) (sin^(2)A cos^(2)B - cos^(2)A sin^(2) B )=(sin^(2)A- sin^(2)B) `
`(ii) (tan^(2)A sec^(2)B - sec^(2)A tan^(2)B)=(tan^(2)A- tan^(2)B) `

Explanation

To prove the given identities, we will tackle each part step by step.

### Part (i): Prove that
\[ \sin^2 A \cos^2 B - \cos^2 A \sin^2 B = \sin^2 A - \sin^2 B \]

**Step 1: Rewrite \(\cos^2 B\) and \(\cos^2 A\) using the Pythagorean identity.**
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